-b^2+6b+2=0

Solution for -b^2+6b+2=0 equation:

-b^2+6b+2=0

We add all the numbers together, and all the variables

-1b^2+6b+2=0

a = -1; b = 6; c = +2;
Δ = b2-4ac
Δ = 62-4·(-1)·2
Δ = 44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{44}=\sqrt{4*11}=\sqrt{4}*\sqrt{11}=2\sqrt{11}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{11}}{2*-1}=\frac{-6-2\sqrt{11}}{-2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{11}}{2*-1}=\frac{-6+2\sqrt{11}}{-2}
$